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Multiplying two signals with opposite phases. - RF Cafe Forums
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nevershadow |
Post subject: Multiplying two signals with opposite phases.
Posted: Wed Jul 18, 2012 5:31 am
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Joined: Wed Jul 18, 2012 5:13 am Posts: 1
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Hi, im new to this forum and i am not sure i am posting this question in the right place
but here it goes. If i have two baseband signals- u1(t) = A1(t)cos(wt+p(t)) and u2(t)
= A2(t)cos(wt-p(t)), where A1 and A2 are the amplitude changes in time in its band(which
is 100 MHz for example) and p(t) is the phase changes in time in their band. both
signals reside in frequency - w. so they basicly overlap if put together. now we
multiply the first on the second and filter out the low frequencies - so basicly we
receive A1(t)*A2(t)cos(2wt).
my question is this- if i mentally divide u1
by half (take the first 50 MHz of the band) and u2 by half and then multiply all 4 halfs
between themselves (and take hgher frequencies) will i receive the initial output -
A1(t)*A2(t)cos(2wt)?
Thanks in advance.
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Posted 11/12/2012
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